Base | Representation |
---|---|

bin | 1100110101010011110110… |

… | …0110101111101010011101 |

3 | 1211221220101020110120000101 |

4 | 3031110331212233222131 |

5 | 3322134240242243422 |

6 | 50002013421101101 |

7 | 2654261660513611 |

oct | 315247546575235 |

9 | 54856336416011 |

10 | 14110001134237 |

11 | 455002187a988 |

12 | 16ba7429b7791 |

13 | 7b474b75a1a8 |

14 | 36acdb869341 |

15 | 19707816bc27 |

hex | cd53d9afa9d |

14110001134237 has 2 divisors, whose sum is σ = 14110001134238. Its totient is φ = 14110001134236.

The previous prime is 14110001134199. The next prime is 14110001134297. The reversal of 14110001134237 is 73243110001141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11459809234756 + 2650191899481 = 3385234^2 + 1627941^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^{k}-14110001134237 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14110001134297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055000567118 + 7055000567119.

It is an arithmetic number, because the mean of its divisors is an integer number (7055000567119).

Almost surely, 2^{14110001134237} is an apocalyptic number.

It is an amenable number.

14110001134237 is a deficient number, since it is larger than the sum of its proper divisors (1).

14110001134237 is an equidigital number, since it uses as much as digits as its factorization.

14110001134237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 14110001134237 its reverse (73243110001141), we get a palindrome (87353111135378).

The spelling of 14110001134237 in words is "fourteen trillion, one hundred ten billion, one million, one hundred thirty-four thousand, two hundred thirty-seven".

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