Base | Representation |
---|---|
bin | 11010010010000100… |
… | …10011101000001101 |
3 | 1100102100220122000020 |
4 | 31021002103220031 |
5 | 212344210241331 |
6 | 10252051252353 |
7 | 1006444042455 |
oct | 151102235015 |
9 | 40370818006 |
10 | 14110243341 |
11 | 5a90956737 |
12 | 28995aa0b9 |
13 | 143b3cac1c |
14 | 97bdb2d65 |
15 | 578b5cc96 |
hex | 349093a0d |
14110243341 has 8 divisors (see below), whose sum is σ = 18866064960. Its totient is φ = 9380625312.
The previous prime is 14110243337. The next prime is 14110243369. The reversal of 14110243341 is 14334201141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14110243341 - 22 = 14110243337 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14110243241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6549640 + ... + 6551793.
It is an arithmetic number, because the mean of its divisors is an integer number (2358258120).
Almost surely, 214110243341 is an apocalyptic number.
It is an amenable number.
14110243341 is a deficient number, since it is larger than the sum of its proper divisors (4755821619).
14110243341 is a wasteful number, since it uses less digits than its factorization.
14110243341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13101795.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 14110243341 its reverse (14334201141), we get a palindrome (28444444482).
The spelling of 14110243341 in words is "fourteen billion, one hundred ten million, two hundred forty-three thousand, three hundred forty-one".
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