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14111000000 = 2656103137
BaseRepresentation
bin11010010010001010…
…01100010111000000
31100102102100001221122
431021011030113000
5212344404000000
610252115411412
71006453343456
oct151105142700
940372301848
1014111000000
115a91323179
1228998b3b68
13143b604456
1497c12c9d6
15578c5c085
hex34914c5c0

14111000000 has 196 divisors, whose sum is σ = 35599231824. Its totient is φ = 5548800000.

The previous prime is 14110999963. The next prime is 14111000039. The reversal of 14111000000 is 11141.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 102999932 + ... + 103000068.

Almost surely, 214111000000 is an apocalyptic number.

14111000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14111000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17799615912).

14111000000 is an abundant number, since it is smaller than the sum of its proper divisors (21488231824).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14111000000 is an frugal number, since it uses more digits than its factorization.

14111000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 282 (or 247 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 8.

Adding to 14111000000 its reverse (11141), we get a palindrome (14111011141).

The spelling of 14111000000 in words is "fourteen billion, one hundred eleven million", and thus it is an aban number.