1411101210013 has 4 divisors (see below), whose sum is σ = 1539383138208. Its totient is φ = 1282819281820.

The previous prime is 1411101209933. The next prime is 1411101210023. The reversal of 1411101210013 is 3100121011141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1411101210013 - 2³⁷ = 1273662256541 is a prime.

It is a super-3 number, since 3×1411101210013³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411101210023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64140964081 + ... + 64140964102.

It is an arithmetic number, because the mean of its divisors is an integer number (384845784552).

Almost surely, 2^{1411101210013} is an apocalyptic number.

It is an amenable number.

1411101210013 is a deficient number, since it is larger than the sum of its proper divisors (128281928195).

1411101210013 is a wasteful number, since it uses less digits than its factorization.

1411101210013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128281928194.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 1411101210013 its reverse (3100121011141), we get a palindrome (4511222221154).

The spelling of 1411101210013 in words is "one trillion, four hundred eleven billion, one hundred one million, two hundred ten thousand, thirteen".