Base | Representation |
---|---|
bin | 1100110101010111100111… |
… | …1111011111011001111101 |
3 | 1211221222222211211101100011 |
4 | 3031111321333133121331 |
5 | 3322143324122113310 |
6 | 50002302131503221 |
7 | 2654326042060261 |
oct | 315257177373175 |
9 | 54858884741304 |
10 | 14111014254205 |
11 | 45504a1744a10 |
12 | 16ba986157b11 |
13 | 7b488060c06b |
14 | 36ad962300a1 |
15 | 1970d709078a |
hex | cd579fdf67d |
14111014254205 has 32 divisors (see below), whose sum is σ = 18494016307200. Its totient is φ = 10250661326400.
The previous prime is 14111014254191. The next prime is 14111014254301. The reversal of 14111014254205 is 50245241011141.
It is a de Polignac number, because none of the positive numbers 2k-14111014254205 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 465403036 + ... + 465433354.
It is an arithmetic number, because the mean of its divisors is an integer number (577938009600).
Almost surely, 214111014254205 is an apocalyptic number.
It is an amenable number.
14111014254205 is a deficient number, since it is larger than the sum of its proper divisors (4383002052995).
14111014254205 is a wasteful number, since it uses less digits than its factorization.
14111014254205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39865.
The product of its (nonzero) digits is 6400, while the sum is 31.
Adding to 14111014254205 its reverse (50245241011141), we get a palindrome (64356255265346).
The spelling of 14111014254205 in words is "fourteen trillion, one hundred eleven billion, fourteen million, two hundred fifty-four thousand, two hundred five".
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