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1411103020140 = 2234511254331139
BaseRepresentation
bin10100100010001100010…
…010110101010001101100
311222220022012021122210000
4110202030102311101230
5141104414333121030
63000130214544300
7203643306524112
oct24421422652154
94886265248700
101411103020140
114a449995a6a0
121a9593668090
13a30b2c91888
144c425055ab2
1526a8cc9d860
hex1488c4b546c

1411103020140 has 240 divisors, whose sum is σ = 4831162237440. Its totient is φ = 341940078720.

The previous prime is 1411103020139. The next prime is 1411103020189. The reversal of 1411103020140 is 410203011141.

1411103020140 is a `hidden beast` number, since 1 + 411 + 10 + 3 + 0 + 201 + 40 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 45300691 + ... + 45331829.

It is an arithmetic number, because the mean of its divisors is an integer number (20129842656).

Almost surely, 21411103020140 is an apocalyptic number.

1411103020140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1411103020140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2415581118720).

1411103020140 is an abundant number, since it is smaller than the sum of its proper divisors (3420059217300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1411103020140 is a wasteful number, since it uses less digits than its factorization.

1411103020140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33714 (or 33703 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 1411103020140 its reverse (410203011141), we get a palindrome (1821306031281).

The spelling of 1411103020140 in words is "one trillion, four hundred eleven billion, one hundred three million, twenty thousand, one hundred forty".