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14111032134202 = 27055516067101
BaseRepresentation
bin1100110101010111101100…
…0011101100101000111010
31211222000001002110210002021
43031111323003230220322
53322143343211243302
650002304011025054
72654326350046453
oct315257303545072
954860032423067
1014111032134202
114550500847473
1216ba99013b18a
137b488422c543
1436ad9876612a
151970d8923437
hexcd57b0eca3a

14111032134202 has 4 divisors (see below), whose sum is σ = 21166548201306. Its totient is φ = 7055516067100.

The previous prime is 14111032134179. The next prime is 14111032134211. The reversal of 14111032134202 is 20243123011141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11370255864361 + 2740776269841 = 3371981^2 + 1655529^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3527758033549 + ... + 3527758033552.

Almost surely, 214111032134202 is an apocalyptic number.

14111032134202 is a deficient number, since it is larger than the sum of its proper divisors (7055516067104).

14111032134202 is an equidigital number, since it uses as much as digits as its factorization.

14111032134202 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7055516067103.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14111032134202 its reverse (20243123011141), we get a palindrome (34354155145343).

The spelling of 14111032134202 in words is "fourteen trillion, one hundred eleven billion, thirty-two million, one hundred thirty-four thousand, two hundred two".

Divisors: 1 2 7055516067101 14111032134202