Base | Representation |
---|---|
bin | 1100110101010111101100… |
… | …1011110001110000011010 |
3 | 1211222000001020110101120212 |
4 | 3031111323023301300122 |
5 | 3322143344232033224 |
6 | 50002304124251122 |
7 | 2654326404050636 |
oct | 315257313616032 |
9 | 54860036411525 |
10 | 14111034252314 |
11 | 4550501a6387a |
12 | 16ba9909a0aa2 |
13 | 7b48847c166c |
14 | 36ad98b57dc6 |
15 | 1970d8be0d0e |
hex | cd57b2f1c1a |
14111034252314 has 4 divisors (see below), whose sum is σ = 21166551378474. Its totient is φ = 7055517126156.
The previous prime is 14111034252311. The next prime is 14111034252353. The reversal of 14111034252314 is 41325243011141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13938088890625 + 172945361689 = 3733375^2 + 415867^2 .
It is not an unprimeable number, because it can be changed into a prime (14111034252311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3527758563077 + ... + 3527758563080.
Almost surely, 214111034252314 is an apocalyptic number.
14111034252314 is a deficient number, since it is larger than the sum of its proper divisors (7055517126160).
14111034252314 is an equidigital number, since it uses as much as digits as its factorization.
14111034252314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7055517126159.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 14111034252314 its reverse (41325243011141), we get a palindrome (55436277263455).
The spelling of 14111034252314 in words is "fourteen trillion, one hundred eleven billion, thirty-four million, two hundred fifty-two thousand, three hundred fourteen".
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