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141111098153 is a prime number
BaseRepresentation
bin1000001101101011100…
…0000111101100101001
3111111020021102111212122
42003122320013230221
54302443420120103
6144454152321025
713123602354344
oct2033270075451
9444207374778
10141111098153
1154932599683
12234219a3175
13103cab2a31c
146b8901945b
153a0d54ab38
hex20dae07b29

141111098153 has 2 divisors, whose sum is σ = 141111098154. Its totient is φ = 141111098152.

The previous prime is 141111098123. The next prime is 141111098159. The reversal of 141111098153 is 351890111141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119050531369 + 22060566784 = 345037^2 + 148528^2 .

It is a cyclic number.

It is not a de Polignac number, because 141111098153 - 222 = 141106903849 is a prime.

It is a super-2 number, since 2×1411110981532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141111098159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70555549076 + 70555549077.

It is an arithmetic number, because the mean of its divisors is an integer number (70555549077).

Almost surely, 2141111098153 is an apocalyptic number.

It is an amenable number.

141111098153 is a deficient number, since it is larger than the sum of its proper divisors (1).

141111098153 is an equidigital number, since it uses as much as digits as its factorization.

141111098153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 35.

The spelling of 141111098153 in words is "one hundred forty-one billion, one hundred eleven million, ninety-eight thousand, one hundred fifty-three".