Base | Representation |
---|---|
bin | 100000000101011100000110… |
… | …010000101100110101100111 |
3 | 200111122002211000121120002121 |
4 | 200011130012100230311213 |
5 | 121443431322410120320 |
6 | 1220041341010050411 |
7 | 41502644313442066 |
oct | 4005340620546547 |
9 | 614562730546077 |
10 | 141111255551335 |
11 | 40a64a46aa5583 |
12 | 139b0381b79a07 |
13 | 609797134a704 |
14 | 26bbb6d5881dd |
15 | 114a9631aa8aa |
hex | 80570642cd67 |
141111255551335 has 32 divisors (see below), whose sum is σ = 183469447732032. Its totient is φ = 103774462310400.
The previous prime is 141111255551327. The next prime is 141111255551351. The reversal of 141111255551335 is 533155552111141.
It is not a de Polignac number, because 141111255551335 - 23 = 141111255551327 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 141111255551291 and 141111255551300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 124807377 + ... + 125932933.
It is an arithmetic number, because the mean of its divisors is an integer number (5733420241626).
Almost surely, 2141111255551335 is an apocalyptic number.
141111255551335 is a deficient number, since it is larger than the sum of its proper divisors (42358192180697).
141111255551335 is a wasteful number, since it uses less digits than its factorization.
141111255551335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1159923.
The product of its digits is 225000, while the sum is 43.
The spelling of 141111255551335 in words is "one hundred forty-one trillion, one hundred eleven billion, two hundred fifty-five million, five hundred fifty-one thousand, three hundred thirty-five".
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