Base | Representation |
---|---|
bin | 11010010010001011… |
… | …11101010010010011 |
3 | 1100102102201020211222 |
4 | 31021011331102103 |
5 | 212344431403103 |
6 | 10252123555255 |
7 | 1006455136646 |
oct | 151105752223 |
9 | 40372636758 |
10 | 14111200403 |
11 | 5a9144a7a3 |
12 | 289998bb2b |
13 | 143b674731 |
14 | 97c181a5d |
15 | 578c9b638 |
hex | 34917d493 |
14111200403 has 8 divisors (see below), whose sum is σ = 14584934400. Its totient is φ = 13638624840.
The previous prime is 14111200391. The next prime is 14111200409. The reversal of 14111200403 is 30400211141.
It is a happy number.
14111200403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14111200403 - 222 = 14107006099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14111200409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 264803 + ... + 313596.
It is an arithmetic number, because the mean of its divisors is an integer number (1823116800).
Almost surely, 214111200403 is an apocalyptic number.
14111200403 is a deficient number, since it is larger than the sum of its proper divisors (473733997).
14111200403 is an equidigital number, since it uses as much as digits as its factorization.
14111200403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 579217.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 14111200403 its reverse (30400211141), we get a palindrome (44511411544).
The spelling of 14111200403 in words is "fourteen billion, one hundred eleven million, two hundred thousand, four hundred three".
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