1411121341 has 4 divisors (see below), whose sum is σ = 1612710112. Its totient is φ = 1209532572.

The previous prime is 1411121339. The next prime is 1411121351. The reversal of 1411121341 is 1431211141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1431211141 = 13463 ⋅106307.

It is a cyclic number.

It is not a de Polignac number, because 1411121341 - 2¹ = 1411121339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411121311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100794375 + ... + 100794388.

It is an arithmetic number, because the mean of its divisors is an integer number (403177528).

Almost surely, 2^1411121341 is an apocalyptic number.

It is an amenable number.

1411121341 is a deficient number, since it is larger than the sum of its proper divisors (201588771).

1411121341 is an equidigital number, since it uses as much as digits as its factorization.

1411121341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 201588770.

The product of its digits is 96, while the sum is 19.

The square root of 1411121341 is about 37564.8950617461. The cubic root of 1411121341 is about 1121.6433520742.

Adding to 1411121341 its reverse (1431211141), we get a palindrome (2842332482).

The spelling of 1411121341 in words is "one billion, four hundred eleven million, one hundred twenty-one thousand, three hundred forty-one".