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1411124971 is a prime number
BaseRepresentation
bin101010000011100…
…0000111011101011
310122100021120112211
41110013000323223
510342221444341
6352005145551
746653235654
oct12407007353
93570246484
101411124971
116645a8093
123346bb2b7
131964753b9
14d55aa52b
1583d41181
hex541c0eeb

1411124971 has 2 divisors, whose sum is σ = 1411124972. Its totient is φ = 1411124970.

The previous prime is 1411124951. The next prime is 1411124977. The reversal of 1411124971 is 1794211141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1411124971 - 213 = 1411116779 is a prime.

It is not a weakly prime, because it can be changed into another prime (1411124977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705562485 + 705562486.

It is an arithmetic number, because the mean of its divisors is an integer number (705562486).

Almost surely, 21411124971 is an apocalyptic number.

1411124971 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411124971 is an equidigital number, since it uses as much as digits as its factorization.

1411124971 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2016, while the sum is 31.

The square root of 1411124971 is about 37564.9433781019. The cubic root of 1411124971 is about 1121.6443138535.

The spelling of 1411124971 in words is "one billion, four hundred eleven million, one hundred twenty-four thousand, nine hundred seventy-one".