1411131144403 has 2 divisors, whose sum is σ = 1411131144404. Its totient is φ = 1411131144402.

The previous prime is 1411131144361. The next prime is 1411131144463. The reversal of 1411131144403 is 3044411311141.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411131144403 is a prime.

It is a super-2 number, since 2×1411131144403² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1411131144463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705565572201 + 705565572202.

It is an arithmetic number, because the mean of its divisors is an integer number (705565572202).

Almost surely, 2^{1411131144403} is an apocalyptic number.

1411131144403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411131144403 is an equidigital number, since it uses as much as digits as its factorization.

1411131144403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 1411131144403 its reverse (3044411311141), we get a palindrome (4455542455544).

The spelling of 1411131144403 in words is "one trillion, four hundred eleven billion, one hundred thirty-one million, one hundred forty-four thousand, four hundred three".