Base | Representation |
---|---|
bin | 100000000101011101111010… |
… | …001110110011010001001010 |
3 | 200111122021211121201021122000 |
4 | 200011131322032303101022 |
5 | 121443444314002213232 |
6 | 1220042302032211430 |
7 | 41503043450326446 |
oct | 4005357216632112 |
9 | 614567747637560 |
10 | 141113201210442 |
11 | 40a658552a700a |
12 | 139b0825699b76 |
13 | 6097bc14798a6 |
14 | 26bbcb5b39826 |
15 | 114aa28dd727c |
hex | 80577a3b344a |
141113201210442 has 16 divisors (see below), whose sum is σ = 313584891578880. Its totient is φ = 47037733736796.
The previous prime is 141113201210431. The next prime is 141113201210479. The reversal of 141113201210442 is 244012102311141.
141113201210442 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 1 + 3 + 2 + 0 + 1 + 210 + 442 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1306603714858 + ... + 1306603714965.
It is an arithmetic number, because the mean of its divisors is an integer number (19599055723680).
Almost surely, 2141113201210442 is an apocalyptic number.
141113201210442 is an abundant number, since it is smaller than the sum of its proper divisors (172471690368438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141113201210442 is a wasteful number, since it uses less digits than its factorization.
141113201210442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2613207429834 (or 2613207429828 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 27.
Adding to 141113201210442 its reverse (244012102311141), we get a palindrome (385125303521583).
The spelling of 141113201210442 in words is "one hundred forty-one trillion, one hundred thirteen billion, two hundred one million, two hundred ten thousand, four hundred forty-two".
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