141113201210431 has 2 divisors, whose sum is σ = 141113201210432. Its totient is φ = 141113201210430.

The previous prime is 141113201210393. The next prime is 141113201210479. The reversal of 141113201210431 is 134012102311141.

It is a weak prime.

It is an emirp because it is prime and its reverse (134012102311141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141113201210431 is a prime.

It is a super-2 number, since 2×141113201210431² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141113201210396 and 141113201210405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141113201210831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70556600605215 + 70556600605216.

It is an arithmetic number, because the mean of its divisors is an integer number (70556600605216).

Almost surely, 2^{141113201210431} is an apocalyptic number.

141113201210431 is a deficient number, since it is larger than the sum of its proper divisors (1).

141113201210431 is an equidigital number, since it uses as much as digits as its factorization.

141113201210431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 141113201210431 its reverse (134012102311141), we get a palindrome (275125303521572).

The spelling of 141113201210431 in words is "one hundred forty-one trillion, one hundred thirteen billion, two hundred one million, two hundred ten thousand, four hundred thirty-one".