14111442440113 has 2 divisors, whose sum is σ = 14111442440114. Its totient is φ = 14111442440112.

The previous prime is 14111442440101. The next prime is 14111442440197. The reversal of 14111442440113 is 31104424411141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7094940758689 + 7016501681424 = 2663633^2 + 2648868^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111442440113 - 2¹³ = 14111442431921 is a prime.

It is not a weakly prime, because it can be changed into another prime (14111442440713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055721220056 + 7055721220057.

It is an arithmetic number, because the mean of its divisors is an integer number (7055721220057).

Almost surely, 2^{14111442440113} is an apocalyptic number.

It is an amenable number.

14111442440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111442440113 is an equidigital number, since it uses as much as digits as its factorization.

14111442440113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 31.

Adding to 14111442440113 its reverse (31104424411141), we get a palindrome (45215866851254).

The spelling of 14111442440113 in words is "fourteen trillion, one hundred eleven billion, four hundred forty-two million, four hundred forty thousand, one hundred thirteen".