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14111464476433 is a prime number
BaseRepresentation
bin1100110101011001010011…
…0100111100111100010001
31211222001011020000001010111
43031112110310330330101
53322200234401221213
650002414533401321
72654343146643442
oct315262464747421
954861136001114
1014111464476433
1145507028a25a5
1216baa90a99241
137b4922985c4c
1436add9d492c9
15197111874a3d
hexcd594d3cf11

14111464476433 has 2 divisors, whose sum is σ = 14111464476434. Its totient is φ = 14111464476432.

The previous prime is 14111464476377. The next prime is 14111464476449. The reversal of 14111464476433 is 33467446411141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12009045675649 + 2102418800784 = 3465407^2 + 1449972^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111464476433 - 241 = 11912441220881 is a prime.

It is not a weakly prime, because it can be changed into another prime (14111464476463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055732238216 + 7055732238217.

It is an arithmetic number, because the mean of its divisors is an integer number (7055732238217).

Almost surely, 214111464476433 is an apocalyptic number.

It is an amenable number.

14111464476433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111464476433 is an equidigital number, since it uses as much as digits as its factorization.

14111464476433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2322432, while the sum is 49.

The spelling of 14111464476433 in words is "fourteen trillion, one hundred eleven billion, four hundred sixty-four million, four hundred seventy-six thousand, four hundred thirty-three".