Base | Representation |
---|---|
bin | 11010010010001110… |
… | …01011111100000001 |
3 | 1100102110022121202202 |
4 | 31021013023330001 |
5 | 212400022210221 |
6 | 10252134522545 |
7 | 1006460651123 |
oct | 151107137401 |
9 | 40373277682 |
10 | 14111522561 |
11 | 5a9164a844 |
12 | 2899b06455 |
13 | 143b758266 |
14 | 97c227213 |
15 | 578d11d0b |
hex | 3491cbf01 |
14111522561 has 2 divisors, whose sum is σ = 14111522562. Its totient is φ = 14111522560.
The previous prime is 14111522543. The next prime is 14111522573. The reversal of 14111522561 is 16522511141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10612090225 + 3499432336 = 103015^2 + 59156^2 .
It is an emirp because it is prime and its reverse (16522511141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14111522561 - 26 = 14111522497 is a prime.
It is a super-2 number, since 2×141115225612 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11111522561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055761280 + 7055761281.
It is an arithmetic number, because the mean of its divisors is an integer number (7055761281).
Almost surely, 214111522561 is an apocalyptic number.
It is an amenable number.
14111522561 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111522561 is an equidigital number, since it uses as much as digits as its factorization.
14111522561 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2400, while the sum is 29.
The spelling of 14111522561 in words is "fourteen billion, one hundred eleven million, five hundred twenty-two thousand, five hundred sixty-one".
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