Base | Representation |
---|---|
bin | 100000000101100100100010… |
… | …110011101010011110000010 |
3 | 200111122222020001021110222121 |
4 | 200011210202303222132002 |
5 | 121444103411022211224 |
6 | 1220045440531154454 |
7 | 41503415123466661 |
oct | 4005444263523602 |
9 | 614588201243877 |
10 | 141120324413314 |
11 | 40a6888014a834 |
12 | 139b2093145a2a |
13 | 609878815b52c |
14 | 26bc38dba6dd8 |
15 | 114ace443abe4 |
hex | 805922cea782 |
141120324413314 has 4 divisors (see below), whose sum is σ = 211680486619974. Its totient is φ = 70560162206656.
The previous prime is 141120324413287. The next prime is 141120324413323. The reversal of 141120324413314 is 413314423021141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 87627703175089 + 53492621238225 = 9360967^2 + 7313865^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 141120324413314.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35280081103327 + ... + 35280081103330.
Almost surely, 2141120324413314 is an apocalyptic number.
141120324413314 is a deficient number, since it is larger than the sum of its proper divisors (70560162206660).
141120324413314 is an equidigital number, since it uses as much as digits as its factorization.
141120324413314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70560162206659.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 141120324413314 its reverse (413314423021141), we get a palindrome (554434747434455).
The spelling of 141120324413314 in words is "one hundred forty-one trillion, one hundred twenty billion, three hundred twenty-four million, four hundred thirteen thousand, three hundred fourteen".
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