141120340221301 has 4 divisors (see below), whose sum is σ = 161280388824352. Its totient is φ = 120960291618252.

The previous prime is 141120340221299. The next prime is 141120340221347. The reversal of 141120340221301 is 103122043021141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141120340221301 - 2¹ = 141120340221299 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141120340021301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10080024301515 + ... + 10080024301528.

It is an arithmetic number, because the mean of its divisors is an integer number (40320097206088).

Almost surely, 2^{141120340221301} is an apocalyptic number.

It is an amenable number.

141120340221301 is a deficient number, since it is larger than the sum of its proper divisors (20160048603051).

141120340221301 is an equidigital number, since it uses as much as digits as its factorization.

141120340221301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20160048603050.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 141120340221301 its reverse (103122043021141), we get a palindrome (244242383242442).

The spelling of 141120340221301 in words is "one hundred forty-one trillion, one hundred twenty billion, three hundred forty million, two hundred twenty-one thousand, three hundred one".