Base | Representation |
---|---|
bin | 10100100010010010010… |
… | …001111010010101010001 |
3 | 11222220120012020121200012 |
4 | 110202102101322111101 |
5 | 141110121040121001 |
6 | 3000144203204305 |
7 | 203645636224163 |
oct | 24422221722521 |
9 | 4886505217605 |
10 | 1411203442001 |
11 | 4a454060a071 |
12 | 1a9601216695 |
13 | a30caa223b2 |
14 | 4c434516933 |
15 | 26a969d82bb |
hex | 1489247a551 |
1411203442001 has 2 divisors, whose sum is σ = 1411203442002. Its totient is φ = 1411203442000.
The previous prime is 1411203441997. The next prime is 1411203442031. The reversal of 1411203442001 is 1002443021141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1332269977600 + 78933464401 = 1154240^2 + 280951^2 .
It is a cyclic number.
It is not a de Polignac number, because 1411203442001 - 22 = 1411203441997 is a prime.
It is not a weakly prime, because it can be changed into another prime (1411203442031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705601721000 + 705601721001.
It is an arithmetic number, because the mean of its divisors is an integer number (705601721001).
Almost surely, 21411203442001 is an apocalyptic number.
It is an amenable number.
1411203442001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411203442001 is an equidigital number, since it uses as much as digits as its factorization.
1411203442001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1411203442001 its reverse (1002443021141), we get a palindrome (2413646463142).
The spelling of 1411203442001 in words is "one trillion, four hundred eleven billion, two hundred three million, four hundred forty-two thousand, one".
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