Base | Representation |
---|---|
bin | 11010010010010010… |
… | …11011011101011111 |
3 | 1100102111102111011201 |
4 | 31021021123131133 |
5 | 212400200013211 |
6 | 10252155300331 |
7 | 1006465650046 |
oct | 151111333537 |
9 | 40374374151 |
10 | 14112110431 |
11 | 5a91a11491 |
12 | 289a14a6a7 |
13 | 143b902a03 |
14 | 97c33b55d |
15 | 578dcb0c1 |
hex | 34925b75f |
14112110431 has 4 divisors (see below), whose sum is σ = 14942234592. Its totient is φ = 13281986272.
The previous prime is 14112110423. The next prime is 14112110447. The reversal of 14112110431 is 13401121141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14112110431 - 23 = 14112110423 is a prime.
It is a super-2 number, since 2×141121104312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14112110399 and 14112110408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14112114431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 415062055 + ... + 415062088.
It is an arithmetic number, because the mean of its divisors is an integer number (3735558648).
Almost surely, 214112110431 is an apocalyptic number.
14112110431 is a deficient number, since it is larger than the sum of its proper divisors (830124161).
14112110431 is an equidigital number, since it uses as much as digits as its factorization.
14112110431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 830124160.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 14112110431 its reverse (13401121141), we get a palindrome (27513231572).
The spelling of 14112110431 in words is "fourteen billion, one hundred twelve million, one hundred ten thousand, four hundred thirty-one".
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