Base | Representation |
---|---|
bin | 10000110100101… |
… | …01011111001001 |
3 | 100211112201021112 |
4 | 20122111133021 |
5 | 242111341411 |
6 | 22000420105 |
7 | 3332340614 |
oct | 1032253711 |
9 | 324481245 |
10 | 141121481 |
11 | 72728726 |
12 | 3b317635 |
13 | 23310947 |
14 | 14a5717b |
15 | c5c8b8b |
hex | 86957c9 |
141121481 has 2 divisors, whose sum is σ = 141121482. Its totient is φ = 141121480.
The previous prime is 141121469. The next prime is 141121489. The reversal of 141121481 is 184121141.
141121481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129595456 + 11526025 = 11384^2 + 3395^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141121481 is a prime.
It is a super-2 number, since 2×1411214812 = 39830544799266722, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (141121489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70560740 + 70560741.
It is an arithmetic number, because the mean of its divisors is an integer number (70560741).
Almost surely, 2141121481 is an apocalyptic number.
It is an amenable number.
141121481 is a deficient number, since it is larger than the sum of its proper divisors (1).
141121481 is an equidigital number, since it uses as much as digits as its factorization.
141121481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 256, while the sum is 23.
The square root of 141121481 is about 11879.4562586004. The cubic root of 141121481 is about 520.6322204279.
The spelling of 141121481 in words is "one hundred forty-one million, one hundred twenty-one thousand, four hundred eighty-one".
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