Base | Representation |
---|---|
bin | 100000000101100110010010… |
… | …100111011000001101101011 |
3 | 200111200011001202222101211012 |
4 | 200011212102213120031223 |
5 | 121444121231230203003 |
6 | 1220050351020454135 |
7 | 41503512451662242 |
oct | 4005462247301553 |
9 | 614604052871735 |
10 | 141122200241003 |
11 | 40a69652a95953 |
12 | 139b25173aa34b |
13 | 60989c697a847 |
14 | 26bc4cad7b959 |
15 | 114ada3e718d8 |
hex | 8059929d836b |
141122200241003 has 2 divisors, whose sum is σ = 141122200241004. Its totient is φ = 141122200241002.
The previous prime is 141122200240991. The next prime is 141122200241017. The reversal of 141122200241003 is 300142002221141.
It is a weak prime.
It is an emirp because it is prime and its reverse (300142002221141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141122200241003 - 226 = 141122133132139 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 141122200241003.
It is not a weakly prime, because it can be changed into another prime (141122200241093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561100120501 + 70561100120502.
It is an arithmetic number, because the mean of its divisors is an integer number (70561100120502).
Almost surely, 2141122200241003 is an apocalyptic number.
141122200241003 is a deficient number, since it is larger than the sum of its proper divisors (1).
141122200241003 is an equidigital number, since it uses as much as digits as its factorization.
141122200241003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 141122200241003 its reverse (300142002221141), we get a palindrome (441264202462144).
The spelling of 141122200241003 in words is "one hundred forty-one trillion, one hundred twenty-two billion, two hundred million, two hundred forty-one thousand, three".
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