Base | Representation |
---|---|
bin | 100000000101100110100000… |
… | …011000011111110100110011 |
3 | 200111200011122212121101212111 |
4 | 200011212200120133310303 |
5 | 121444122214343033133 |
6 | 1220050425551310151 |
7 | 41503521255166366 |
oct | 4005464030376463 |
9 | 614604585541774 |
10 | 141122431221043 |
11 | 40a69761408648 |
12 | 139b258081b357 |
13 | 6098a32790c1c |
14 | 26bc50d9060dd |
15 | 114adb939a1cd |
hex | 8059a061fd33 |
141122431221043 has 2 divisors, whose sum is σ = 141122431221044. Its totient is φ = 141122431221042.
The previous prime is 141122431220951. The next prime is 141122431221049. The reversal of 141122431221043 is 340122134221141.
It is a strong prime.
It is an emirp because it is prime and its reverse (340122134221141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141122431221043 - 225 = 141122397666611 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141122431220996 and 141122431221014.
It is not a weakly prime, because it can be changed into another prime (141122431221049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561215610521 + 70561215610522.
It is an arithmetic number, because the mean of its divisors is an integer number (70561215610522).
Almost surely, 2141122431221043 is an apocalyptic number.
141122431221043 is a deficient number, since it is larger than the sum of its proper divisors (1).
141122431221043 is an equidigital number, since it uses as much as digits as its factorization.
141122431221043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 141122431221043 its reverse (340122134221141), we get a palindrome (481244565442184).
The spelling of 141122431221043 in words is "one hundred forty-one trillion, one hundred twenty-two billion, four hundred thirty-one million, two hundred twenty-one thousand, forty-three".
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