Base | Representation |
---|---|
bin | 1000001101101110010… |
… | …1101000110011010011 |
3 | 111111021002212201121022 |
4 | 2003123211220303103 |
5 | 4303004443431402 |
6 | 144455300150055 |
7 | 13124105651624 |
oct | 2033345506323 |
9 | 444232781538 |
10 | 141123030227 |
11 | 549392a93a3 |
12 | 2342599832b |
13 | 1040044741a |
14 | 6b8a843a4b |
15 | 3a0e6062a2 |
hex | 20db968cd3 |
141123030227 has 2 divisors, whose sum is σ = 141123030228. Its totient is φ = 141123030226.
The previous prime is 141123030211. The next prime is 141123030241. The reversal of 141123030227 is 722030321141.
141123030227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141123030227 - 24 = 141123030211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141123030196 and 141123030205.
It is not a weakly prime, because it can be changed into another prime (141123030277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561515113 + 70561515114.
It is an arithmetic number, because the mean of its divisors is an integer number (70561515114).
Almost surely, 2141123030227 is an apocalyptic number.
141123030227 is a deficient number, since it is larger than the sum of its proper divisors (1).
141123030227 is an equidigital number, since it uses as much as digits as its factorization.
141123030227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 141123030227 its reverse (722030321141), we get a palindrome (863153351368).
The spelling of 141123030227 in words is "one hundred forty-one billion, one hundred twenty-three million, thirty thousand, two hundred twenty-seven".
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