Base | Representation |
---|---|
bin | 100000000101101001000000… |
… | …101010010110010001111111 |
3 | 200111200102121021111111010120 |
4 | 200011221000222112101333 |
5 | 121444143221241130403 |
6 | 1220051552450510023 |
7 | 41503645016461005 |
oct | 4005510052262177 |
9 | 614612537444116 |
10 | 141125120255103 |
11 | 40a6a911294746 |
12 | 139b2bb1295313 |
13 | 609907090823a |
14 | 26bc6c6ac2a75 |
15 | 114aec54b5e53 |
hex | 805a40a9647f |
141125120255103 has 32 divisors (see below), whose sum is σ = 193438350723072. Its totient is φ = 91464437433600.
The previous prime is 141125120255083. The next prime is 141125120255107. The reversal of 141125120255103 is 301552021521141.
It is not a de Polignac number, because 141125120255103 - 26 = 141125120255039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141125120255107) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39697593 + ... + 43106253.
It is an arithmetic number, because the mean of its divisors is an integer number (6044948460096).
Almost surely, 2141125120255103 is an apocalyptic number.
141125120255103 is a deficient number, since it is larger than the sum of its proper divisors (52313230467969).
141125120255103 is a wasteful number, since it uses less digits than its factorization.
141125120255103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3409895.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 141125120255103 its reverse (301552021521141), we get a palindrome (442677141776244).
The spelling of 141125120255103 in words is "one hundred forty-one trillion, one hundred twenty-five billion, one hundred twenty million, two hundred fifty-five thousand, one hundred three".
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