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141125120503 = 1031533189371
BaseRepresentation
bin1000001101101110110…
…1100111000111110111
3111111021020210220220221
42003123231213013313
54303011012324003
6144455413035211
713124132506003
oct2033355470767
9444236726827
10141125120503
115493a4a68a4
1223426625b07
13104009c9983
146b8ac29703
153a0e8ba7bd
hex20dbb671f7

141125120503 has 8 divisors (see below), whose sum is σ = 142506156416. Its totient is φ = 139744294200.

The previous prime is 141125120491. The next prime is 141125120711. The reversal of 141125120503 is 305021521141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141125120503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141125100503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1534408 + ... + 1623778.

It is an arithmetic number, because the mean of its divisors is an integer number (17813269552).

Almost surely, 2141125120503 is an apocalyptic number.

141125120503 is a deficient number, since it is larger than the sum of its proper divisors (1381035913).

141125120503 is a wasteful number, since it uses less digits than its factorization.

141125120503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104805.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 141125120503 its reverse (305021521141), we get a palindrome (446146641644).

The spelling of 141125120503 in words is "one hundred forty-one billion, one hundred twenty-five million, one hundred twenty thousand, five hundred three".

Divisors: 1 103 15331 89371 1579093 9205213 1370146801 141125120503