Base | Representation |
---|---|
bin | 1100110101011101001111… |
… | …0000010110000010111111 |
3 | 1211222010212210121001002011 |
4 | 3031113103300112002333 |
5 | 3322204420134430101 |
6 | 50003111410112051 |
7 | 2654411256506404 |
oct | 315272360260277 |
9 | 54863783531064 |
10 | 14112520233151 |
11 | 45510a483920a |
12 | 16bb12657b627 |
13 | 7b4a60615872 |
14 | 36b09a24c2ab |
15 | 1971743bb751 |
hex | cd5d3c160bf |
14112520233151 has 24 divisors (see below), whose sum is σ = 14703612480000. Its totient is φ = 13541122142352.
The previous prime is 14112520233137. The next prime is 14112520233193. The reversal of 14112520233151 is 15133202521141.
It is not a de Polignac number, because 14112520233151 - 27 = 14112520233023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14112520233551) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 156937000 + ... + 157026898.
It is an arithmetic number, because the mean of its divisors is an integer number (612650520000).
Almost surely, 214112520233151 is an apocalyptic number.
14112520233151 is a deficient number, since it is larger than the sum of its proper divisors (591092246849).
14112520233151 is an equidigital number, since it uses as much as digits as its factorization.
14112520233151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91483 (or 91440 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 14112520233151 its reverse (15133202521141), we get a palindrome (29245722754292).
The spelling of 14112520233151 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred thirty-three thousand, one hundred fifty-one".
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