Base | Representation |
---|---|
bin | 1100110101011101001111… |
… | …0000011010001111111011 |
3 | 1211222010212210121220200122 |
4 | 3031113103300122033323 |
5 | 3322204420141002423 |
6 | 50003111410323455 |
7 | 2654411256610523 |
oct | 315272360321773 |
9 | 54863783556618 |
10 | 14112520250363 |
11 | 45510a4850137 |
12 | 16bb12658958b |
13 | 7b4a60620652 |
14 | 36b09a254683 |
15 | 1971743c18c8 |
hex | cd5d3c1a3fb |
14112520250363 has 2 divisors, whose sum is σ = 14112520250364. Its totient is φ = 14112520250362.
The previous prime is 14112520250321. The next prime is 14112520250393. The reversal of 14112520250363 is 36305202521141.
It is a strong prime.
It is an emirp because it is prime and its reverse (36305202521141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14112520250363 - 26 = 14112520250299 is a prime.
It is a super-3 number, since 3×141125202503633 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (14112520250393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056260125181 + 7056260125182.
It is an arithmetic number, because the mean of its divisors is an integer number (7056260125182).
Almost surely, 214112520250363 is an apocalyptic number.
14112520250363 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112520250363 is an equidigital number, since it uses as much as digits as its factorization.
14112520250363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 14112520250363 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred fifty thousand, three hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •