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141125305222015 = 542167042900343
BaseRepresentation
bin100000000101101001001011…
…101011111100001101111111
3200111200110002011112210000221
4200011221023223330031333
5121444144111114101030
61220052023055202211
741503652423614102
oct4005511353741577
9614613064483027
10141125305222015
1140a6a9a673a064
12139b3043216367
1360990a002ab0a
1426bc7034b0739
15114aed6850e7a
hex805a4bafc37f

141125305222015 has 8 divisors (see below), whose sum is σ = 169752623671008. Its totient is φ = 112632072574560.

The previous prime is 141125305222003. The next prime is 141125305222129. The reversal of 141125305222015 is 510222503521141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 141125305222015 - 221 = 141125303124863 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33521448067 + ... + 33521452276.

It is an arithmetic number, because the mean of its divisors is an integer number (21219077958876).

Almost surely, 2141125305222015 is an apocalyptic number.

141125305222015 is a deficient number, since it is larger than the sum of its proper divisors (28627318448993).

141125305222015 is an equidigital number, since it uses as much as digits as its factorization.

141125305222015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67042900769.

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 141125305222015 its reverse (510222503521141), we get a palindrome (651347808743156).

The spelling of 141125305222015 in words is "one hundred forty-one trillion, one hundred twenty-five billion, three hundred five million, two hundred twenty-two thousand, fifteen".

Divisors: 1 5 421 2105 67042900343 335214501715 28225061044403 141125305222015