Base | Representation |
---|---|
bin | 100000000101101001001011… |
… | …101011111100001101111111 |
3 | 200111200110002011112210000221 |
4 | 200011221023223330031333 |
5 | 121444144111114101030 |
6 | 1220052023055202211 |
7 | 41503652423614102 |
oct | 4005511353741577 |
9 | 614613064483027 |
10 | 141125305222015 |
11 | 40a6a9a673a064 |
12 | 139b3043216367 |
13 | 60990a002ab0a |
14 | 26bc7034b0739 |
15 | 114aed6850e7a |
hex | 805a4bafc37f |
141125305222015 has 8 divisors (see below), whose sum is σ = 169752623671008. Its totient is φ = 112632072574560.
The previous prime is 141125305222003. The next prime is 141125305222129. The reversal of 141125305222015 is 510222503521141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 141125305222015 - 221 = 141125303124863 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33521448067 + ... + 33521452276.
It is an arithmetic number, because the mean of its divisors is an integer number (21219077958876).
Almost surely, 2141125305222015 is an apocalyptic number.
141125305222015 is a deficient number, since it is larger than the sum of its proper divisors (28627318448993).
141125305222015 is an equidigital number, since it uses as much as digits as its factorization.
141125305222015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67042900769.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 141125305222015 its reverse (510222503521141), we get a palindrome (651347808743156).
The spelling of 141125305222015 in words is "one hundred forty-one trillion, one hundred twenty-five billion, three hundred five million, two hundred twenty-two thousand, fifteen".
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