Base | Representation |
---|---|
bin | 1100110101011101010100… |
… | …1111010010100011000011 |
3 | 1211222010221112102112211212 |
4 | 3031113111033102203003 |
5 | 3322204443022404444 |
6 | 50003114055400335 |
7 | 2654412011201165 |
oct | 315272517224303 |
9 | 54863845375755 |
10 | 14112545122499 |
11 | 4551107898a1a |
12 | 16bb1329830ab |
13 | 7b4a6581b5a5 |
14 | 36b09d68a935 |
15 | 19717668619e |
hex | cd5d53d28c3 |
14112545122499 has 2 divisors, whose sum is σ = 14112545122500. Its totient is φ = 14112545122498.
The previous prime is 14112545122493. The next prime is 14112545122561. The reversal of 14112545122499 is 99422154521141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14112545122499 - 216 = 14112545056963 is a prime.
It is not a weakly prime, because it can be changed into another prime (14112545122493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056272561249 + 7056272561250.
It is an arithmetic number, because the mean of its divisors is an integer number (7056272561250).
Almost surely, 214112545122499 is an apocalyptic number.
14112545122499 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112545122499 is an equidigital number, since it uses as much as digits as its factorization.
14112545122499 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1036800, while the sum is 50.
The spelling of 14112545122499 in words is "fourteen trillion, one hundred twelve billion, five hundred forty-five million, one hundred twenty-two thousand, four hundred ninety-nine".
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