14112545333141 has 4 divisors (see below), whose sum is σ = 14112554095500. Its totient is φ = 14112536570784.

The previous prime is 14112545333129. The next prime is 14112545333179. The reversal of 14112545333141 is 14133354521141.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 2126609724100 + 11985935609041 = 1458290^2 + 3462071^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112545333141 - 2¹⁰ = 14112545332117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14112545333095 and 14112545333104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112545333441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1190966 + ... + 5444583.

It is an arithmetic number, because the mean of its divisors is an integer number (3528138523875).

Almost surely, 2^{14112545333141} is an apocalyptic number.

It is an amenable number.

14112545333141 is a deficient number, since it is larger than the sum of its proper divisors (8762359).

14112545333141 is an equidigital number, since it uses as much as digits as its factorization.

14112545333141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8762358.

The product of its digits is 86400, while the sum is 38.

Adding to 14112545333141 its reverse (14133354521141), we get a palindrome (28245899854282).

The spelling of 14112545333141 in words is "fourteen trillion, one hundred twelve billion, five hundred forty-five million, three hundred thirty-three thousand, one hundred forty-one".