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141130121243 is a prime number
BaseRepresentation
bin1000001101110000000…
…0101100000000011011
3111111021121012222122112
42003130000230000123
54303013302334433
6144500112142535
713124223144266
oct2033400540033
9444247188575
10141130121243
1154942301a41
1223428237a4b
1310401a5aba7
146b8b76bcdd
153a10057348
hex20dc02c01b

141130121243 has 2 divisors, whose sum is σ = 141130121244. Its totient is φ = 141130121242.

The previous prime is 141130121201. The next prime is 141130121269. The reversal of 141130121243 is 342121031141.

It is a strong prime.

It is an emirp because it is prime and its reverse (342121031141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141130121243 - 232 = 136835153947 is a prime.

It is a super-2 number, since 2×1411301212432 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141130126243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565060621 + 70565060622.

It is an arithmetic number, because the mean of its divisors is an integer number (70565060622).

Almost surely, 2141130121243 is an apocalyptic number.

141130121243 is a deficient number, since it is larger than the sum of its proper divisors (1).

141130121243 is an equidigital number, since it uses as much as digits as its factorization.

141130121243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 141130121243 its reverse (342121031141), we get a palindrome (483251152384).

The spelling of 141130121243 in words is "one hundred forty-one billion, one hundred thirty million, one hundred twenty-one thousand, two hundred forty-three".