1411304000341 has 4 divisors (see below), whose sum is σ = 1494321882732. Its totient is φ = 1328286117952.

The previous prime is 1411304000297. The next prime is 1411304000363. The reversal of 1411304000341 is 1430004031141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1235676792100 + 175627208241 = 1111610^2 + 419079^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411304000341 - 2¹⁵ = 1411303967573 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411304000371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41508941170 + ... + 41508941203.

It is an arithmetic number, because the mean of its divisors is an integer number (373580470683).

Almost surely, 2^{1411304000341} is an apocalyptic number.

It is an amenable number.

1411304000341 is a deficient number, since it is larger than the sum of its proper divisors (83017882391).

1411304000341 is an equidigital number, since it uses as much as digits as its factorization.

1411304000341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83017882390.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1411304000341 its reverse (1430004031141), we get a palindrome (2841308031482).

The spelling of 1411304000341 in words is "one trillion, four hundred eleven billion, three hundred four million, three hundred forty-one", and thus it is an aban number.