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141131004123103 = 188397491427577
BaseRepresentation
bin100000000101101110011111…
…010111100001011111011111
3200111200222210100000221122121
4200011232133113201133133
5121444242244023414403
61220054404354323411
741504243563515061
oct4005563727413737
9614628710027577
10141131004123103
1140a72360605875
12139b4173889567
13609979a902837
1426bcac4301731
15114b21bd0e3bd
hex805b9f5e17df

141131004123103 has 4 divisors (see below), whose sum is σ = 141138495569520. Its totient is φ = 141123512676688.

The previous prime is 141131004123101. The next prime is 141131004123139. The reversal of 141131004123103 is 301321400131141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141131004123103 - 21 = 141131004123101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141131004123101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3745694950 + ... + 3745732627.

It is an arithmetic number, because the mean of its divisors is an integer number (35284623892380).

Almost surely, 2141131004123103 is an apocalyptic number.

141131004123103 is a deficient number, since it is larger than the sum of its proper divisors (7491446417).

141131004123103 is an equidigital number, since it uses as much as digits as its factorization.

141131004123103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7491446416.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 141131004123103 its reverse (301321400131141), we get a palindrome (442452404254244).

The spelling of 141131004123103 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four million, one hundred twenty-three thousand, one hundred three".

Divisors: 1 18839 7491427577 141131004123103