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1411313120003 is a prime number
BaseRepresentation
bin10100100010011000110…
…100010011001100000011
311222220211211121211121102
4110202120310103030003
5141110332124320003
63000203122045015
7203651440405133
oct24423064231403
94886754554542
101411313120003
114a4597510846
121a9631aa976b
13a3117674017
144c444d06ac3
1526aa1450588
hex14898d13303

1411313120003 has 2 divisors, whose sum is σ = 1411313120004. Its totient is φ = 1411313120002.

The previous prime is 1411313119963. The next prime is 1411313120101. The reversal of 1411313120003 is 3000213131141.

It is a weak prime.

It is an emirp because it is prime and its reverse (3000213131141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1411313120003 - 216 = 1411313054467 is a prime.

It is not a weakly prime, because it can be changed into another prime (1411313120303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705656560001 + 705656560002.

It is an arithmetic number, because the mean of its divisors is an integer number (705656560002).

Almost surely, 21411313120003 is an apocalyptic number.

1411313120003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411313120003 is an equidigital number, since it uses as much as digits as its factorization.

1411313120003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1411313120003 its reverse (3000213131141), we get a palindrome (4411526251144).

The spelling of 1411313120003 in words is "one trillion, four hundred eleven billion, three hundred thirteen million, one hundred twenty thousand, three".