Base | Representation |
---|---|
bin | 100000000101101110110111… |
… | …100101010110101111000011 |
3 | 200111201000211122112001212011 |
4 | 200011232313211112233003 |
5 | 121444244112030332433 |
6 | 1220054512550313351 |
7 | 41504256626031262 |
oct | 4005566745265703 |
9 | 614630748461764 |
10 | 141131410402243 |
11 | 40a7254997a358 |
12 | 139b4267958857 |
13 | 6099833b321b1 |
14 | 26bcb2225c5d9 |
15 | 114b2428133cd |
hex | 805bb7956bc3 |
141131410402243 has 2 divisors, whose sum is σ = 141131410402244. Its totient is φ = 141131410402242.
The previous prime is 141131410402237. The next prime is 141131410402259. The reversal of 141131410402243 is 342204014131141.
It is a weak prime.
It is an emirp because it is prime and its reverse (342204014131141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141131410402243 - 217 = 141131410271171 is a prime.
It is not a weakly prime, because it can be changed into another prime (141131410402643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565705201121 + 70565705201122.
It is an arithmetic number, because the mean of its divisors is an integer number (70565705201122).
Almost surely, 2141131410402243 is an apocalyptic number.
141131410402243 is a deficient number, since it is larger than the sum of its proper divisors (1).
141131410402243 is an equidigital number, since it uses as much as digits as its factorization.
141131410402243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 141131410402243 its reverse (342204014131141), we get a palindrome (483335424533384).
The spelling of 141131410402243 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four hundred ten million, four hundred two thousand, two hundred forty-three".
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