14113212432000 has 1024 divisors, whose sum is σ = 51871083264000. Its totient is φ = 3365941248000.

The previous prime is 14113212431999. The next prime is 14113212432079. The reversal of 14113212432000 is 23421231141.

It is a super-3 number, since 3×14113212432000³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 13453967476 + ... + 13453968524.

It is an arithmetic number, because the mean of its divisors is an integer number (50655354750).

Almost surely, 2^{14113212432000} is an apocalyptic number.

14113212432000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14113212432000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25935541632000).

14113212432000 is an abundant number, since it is smaller than the sum of its proper divisors (37757870832000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14113212432000 is a wasteful number, since it uses less digits than its factorization.

14113212432000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1482 (or 1460 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 14113212432000 its reverse (23421231141), we get a palindrome (14136633663141).

The spelling of 14113212432000 in words is "fourteen trillion, one hundred thirteen billion, two hundred twelve million, four hundred thirty-two thousand".