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14113214012134 = 27056607006067
BaseRepresentation
bin1100110101011111110100…
…0110111001101011100110
31211222012200011001122221001
43031113331012321223212
53322212330241342014
650003304312143514
72654434412520556
oct315277506715346
954865604048831
1014113214012134
114551420419676
1216bb29a997b9a
137b4b41287483
1436b124447166
151971b5260974
hexcd5fd1b9ae6

14113214012134 has 4 divisors (see below), whose sum is σ = 21169821018204. Its totient is φ = 7056607006066.

The previous prime is 14113214012077. The next prime is 14113214012143. The reversal of 14113214012134 is 43121041231141.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×141132140121343 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3528303503032 + ... + 3528303503035.

It is an arithmetic number, because the mean of its divisors is an integer number (5292455254551).

Almost surely, 214113214012134 is an apocalyptic number.

14113214012134 is a deficient number, since it is larger than the sum of its proper divisors (7056607006070).

14113214012134 is an equidigital number, since it uses as much as digits as its factorization.

14113214012134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7056607006069.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 14113214012134 its reverse (43121041231141), we get a palindrome (57234255243275).

The spelling of 14113214012134 in words is "fourteen trillion, one hundred thirteen billion, two hundred fourteen million, twelve thousand, one hundred thirty-four".

Divisors: 1 2 7056607006067 14113214012134