Base | Representation |
---|---|
bin | 1100110101011111110100… |
… | …0110111001101011100110 |
3 | 1211222012200011001122221001 |
4 | 3031113331012321223212 |
5 | 3322212330241342014 |
6 | 50003304312143514 |
7 | 2654434412520556 |
oct | 315277506715346 |
9 | 54865604048831 |
10 | 14113214012134 |
11 | 4551420419676 |
12 | 16bb29a997b9a |
13 | 7b4b41287483 |
14 | 36b124447166 |
15 | 1971b5260974 |
hex | cd5fd1b9ae6 |
14113214012134 has 4 divisors (see below), whose sum is σ = 21169821018204. Its totient is φ = 7056607006066.
The previous prime is 14113214012077. The next prime is 14113214012143. The reversal of 14113214012134 is 43121041231141.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×141132140121343 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3528303503032 + ... + 3528303503035.
It is an arithmetic number, because the mean of its divisors is an integer number (5292455254551).
Almost surely, 214113214012134 is an apocalyptic number.
14113214012134 is a deficient number, since it is larger than the sum of its proper divisors (7056607006070).
14113214012134 is an equidigital number, since it uses as much as digits as its factorization.
14113214012134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7056607006069.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 14113214012134 its reverse (43121041231141), we get a palindrome (57234255243275).
The spelling of 14113214012134 in words is "fourteen trillion, one hundred thirteen billion, two hundred fourteen million, twelve thousand, one hundred thirty-four".
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