141132145320555 has 128 divisors (see below), whose sum is σ = 236288430637056. Its totient is φ = 71885188300800.

The previous prime is 141132145320539. The next prime is 141132145320601. The reversal of 141132145320555 is 555023541231141.

It is not a de Polignac number, because 141132145320555 - 2⁴ = 141132145320539 is a prime.

It is a super-3 number, since 3×141132145320555³ (a number of 43 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1475905645 + ... + 1476001265.

It is an arithmetic number, because the mean of its divisors is an integer number (1846003364352).

Almost surely, 2^{141132145320555} is an apocalyptic number.

141132145320555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

141132145320555 is a deficient number, since it is larger than the sum of its proper divisors (95156285316501).

141132145320555 is a wasteful number, since it uses less digits than its factorization.

141132145320555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96077.

The product of its (nonzero) digits is 360000, while the sum is 42.

Adding to 141132145320555 its reverse (555023541231141), we get a palindrome (696155686551696).

The spelling of 141132145320555 in words is "one hundred forty-one trillion, one hundred thirty-two billion, one hundred forty-five million, three hundred twenty thousand, five hundred fifty-five".