Base | Representation |
---|---|
bin | 1100110101011111110111… |
… | …1010010110101110111011 |
3 | 1211222012201002102221110020 |
4 | 3031113331322112232323 |
5 | 3322212342220003400 |
6 | 50003305513221523 |
7 | 2654434635256305 |
oct | 315277572265673 |
9 | 54865632387406 |
10 | 14113227500475 |
11 | 4551427aa1664 |
12 | 16bb2a34018a3 |
13 | 7b4b43ccaa3c |
14 | 36b126158975 |
15 | 1971b65272a0 |
hex | cd5fde96bbb |
14113227500475 has 24 divisors (see below), whose sum is σ = 23338596405360. Its totient is φ = 7525529848320.
The previous prime is 14113227500461. The next prime is 14113227500479. The reversal of 14113227500475 is 57400572231141.
It is not a de Polignac number, because 14113227500475 - 25 = 14113227500443 is a prime.
It is a super-3 number, since 3×141132275004753 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (14113227500479) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18687490 + ... + 19428039.
It is an arithmetic number, because the mean of its divisors is an integer number (972441516890).
Almost surely, 214113227500475 is an apocalyptic number.
14113227500475 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14113227500475 is a deficient number, since it is larger than the sum of its proper divisors (9225368904885).
14113227500475 is a wasteful number, since it uses less digits than its factorization.
14113227500475 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38120479 (or 38120474 counting only the distinct ones).
The product of its (nonzero) digits is 235200, while the sum is 42.
The spelling of 14113227500475 in words is "fourteen trillion, one hundred thirteen billion, two hundred twenty-seven million, five hundred thousand, four hundred seventy-five".
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