14113300121 has 2 divisors, whose sum is σ = 14113300122. Its totient is φ = 14113300120.

The previous prime is 14113300099. The next prime is 14113300127. The reversal of 14113300121 is 12100331141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13796851600 + 316448521 = 117460^2 + 17789^2 .

It is a cyclic number.

It is not a de Polignac number, because 14113300121 - 2¹⁰ = 14113299097 is a prime.

It is a super-2 number, since 2×14113300121² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14113300121.

It is not a weakly prime, because it can be changed into another prime (14113300127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056650060 + 7056650061.

It is an arithmetic number, because the mean of its divisors is an integer number (7056650061).

Almost surely, 2^14113300121 is an apocalyptic number.

It is an amenable number.

14113300121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113300121 is an equidigital number, since it uses as much as digits as its factorization.

14113300121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 14113300121 its reverse (12100331141), we get a palindrome (26213631262).

The spelling of 14113300121 in words is "fourteen billion, one hundred thirteen million, three hundred thousand, one hundred twenty-one".