Search a number
-
+
14113400302 = 27056700151
BaseRepresentation
bin11010010010011100…
…10110010111101110
31100102120212000112201
431021032112113232
5212401012302202
610252243052114
71006512631441
oct151116262756
940376760481
1014113400302
115a927125a1
12289a67103a
13143bc64b51
1497c595658
15579083387
hex3493965ee

14113400302 has 4 divisors (see below), whose sum is σ = 21170100456. Its totient is φ = 7056700150.

The previous prime is 14113400281. The next prime is 14113400303. The reversal of 14113400302 is 20300431141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20300431141 = 193110512911.

It is a self number, because there is not a number n which added to its sum of digits gives 14113400302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113400303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3528350074 + ... + 3528350077.

It is an arithmetic number, because the mean of its divisors is an integer number (5292525114).

Almost surely, 214113400302 is an apocalyptic number.

14113400302 is a deficient number, since it is larger than the sum of its proper divisors (7056700154).

14113400302 is an equidigital number, since it uses as much as digits as its factorization.

14113400302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7056700153.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 14113400302 its reverse (20300431141), we get a palindrome (34413831443).

The spelling of 14113400302 in words is "fourteen billion, one hundred thirteen million, four hundred thousand, three hundred two".

Divisors: 1 2 7056700151 14113400302