14113411140000 has 480 divisors, whose sum is σ = 47629423505664. Its totient is φ = 3655874560000.

The previous prime is 14113411139999. The next prime is 14113411140001. The reversal of 14113411140000 is 4111431141.

It is an interprime number because it is at equal distance from previous prime (14113411139999) and next prime (14113411140001).

It is a tau number, because it is divible by the number of its divisors (480).

It is not an unprimeable number, because it can be changed into a prime (14113411140001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 573167689 + ... + 573192311.

Almost surely, 2^{14113411140000} is an apocalyptic number.

14113411140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14113411140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23814711752832).

14113411140000 is an abundant number, since it is smaller than the sum of its proper divisors (33516012365664).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14113411140000 is a wasteful number, since it uses less digits than its factorization.

14113411140000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24930 (or 24907 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 14113411140000 its reverse (4111431141), we get a palindrome (14117522571141).

The spelling of 14113411140000 in words is "fourteen trillion, one hundred thirteen billion, four hundred eleven million, one hundred forty thousand".