Base | Representation |
---|---|
bin | 1000001101110000111… |
… | …1111100110001110001 |
3 | 111111021212202020210022 |
4 | 2003130033330301301 |
5 | 4303020313401342 |
6 | 144500334013225 |
7 | 13124302146503 |
oct | 2033417746161 |
9 | 444255666708 |
10 | 141134122097 |
11 | 54944594931 |
12 | 23429647215 |
13 | 1040282bc67 |
14 | 6b8c0cdd73 |
15 | 3a105979d2 |
hex | 20dc3fcc71 |
141134122097 has 2 divisors, whose sum is σ = 141134122098. Its totient is φ = 141134122096.
The previous prime is 141134122079. The next prime is 141134122123. The reversal of 141134122097 is 790221431141.
Together with previous prime (141134122079) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 141098648161 + 35473936 = 375631^2 + 5956^2 .
It is a cyclic number.
It is not a de Polignac number, because 141134122097 - 216 = 141134056561 is a prime.
It is not a weakly prime, because it can be changed into another prime (141134122007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70567061048 + 70567061049.
It is an arithmetic number, because the mean of its divisors is an integer number (70567061049).
Almost surely, 2141134122097 is an apocalyptic number.
It is an amenable number.
141134122097 is a deficient number, since it is larger than the sum of its proper divisors (1).
141134122097 is an equidigital number, since it uses as much as digits as its factorization.
141134122097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 35.
The spelling of 141134122097 in words is "one hundred forty-one billion, one hundred thirty-four million, one hundred twenty-two thousand, ninety-seven".
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