14113543741 has 4 divisors (see below), whose sum is σ = 15396593184. Its totient is φ = 12830494300.

The previous prime is 14113543723. The next prime is 14113543753. The reversal of 14113543741 is 14734531141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14113543741 - 2¹³ = 14113535549 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14113543697 and 14113543706.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113543781) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641524705 + ... + 641524726.

It is an arithmetic number, because the mean of its divisors is an integer number (3849148296).

Almost surely, 2^14113543741 is an apocalyptic number.

14113543741 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14113543741 is a deficient number, since it is larger than the sum of its proper divisors (1283049443).

14113543741 is a wasteful number, since it uses less digits than its factorization.

14113543741 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1283049442.

The product of its digits is 20160, while the sum is 34.

The spelling of 14113543741 in words is "fourteen billion, one hundred thirteen million, five hundred forty-three thousand, seven hundred forty-one".