Base | Representation |
---|---|
bin | 11010010010011101… |
… | …11001011101000010 |
3 | 1100102121010022122221 |
4 | 31021032321131002 |
5 | 212401031402002 |
6 | 10252250121254 |
7 | 1006514100415 |
oct | 151116713502 |
9 | 40377108587 |
10 | 14113544002 |
11 | 5a92800558 |
12 | 289a72022a |
13 | 143bcb538c |
14 | 97c5d1b7c |
15 | 5790b0c37 |
hex | 3493b9742 |
14113544002 has 4 divisors (see below), whose sum is σ = 21170316006. Its totient is φ = 7056772000.
The previous prime is 14113543949. The next prime is 14113544047. The reversal of 14113544002 is 20044531141.
14113544002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12814013601 + 1299530401 = 113199^2 + 36049^2 .
It is a super-3 number, since 3×141135440023 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3528385999 + ... + 3528386002.
Almost surely, 214113544002 is an apocalyptic number.
14113544002 is a deficient number, since it is larger than the sum of its proper divisors (7056772004).
14113544002 is an equidigital number, since it uses as much as digits as its factorization.
14113544002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7056772003.
The product of its (nonzero) digits is 1920, while the sum is 25.
The spelling of 14113544002 in words is "fourteen billion, one hundred thirteen million, five hundred forty-four thousand, two".
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