Base | Representation |
---|---|
bin | 100000000101110010100111… |
… | …110110011100010000001111 |
3 | 200111201102020120120122020212 |
4 | 200011302213312130100033 |
5 | 121444330341000210020 |
6 | 1220100420545033035 |
7 | 41504461544043521 |
oct | 4005624766342017 |
9 | 614642216518225 |
10 | 141135441413135 |
11 | 40a74228314514 |
12 | 139b4bb192577b |
13 | 609a026cc0a40 |
14 | 26bcdc5765a11 |
15 | 114b3cb661cc5 |
hex | 805ca7d9c40f |
141135441413135 has 16 divisors (see below), whose sum is σ = 182394767199456. Its totient is φ = 104220609138048.
The previous prime is 141135441413129. The next prime is 141135441413191. The reversal of 141135441413135 is 531314144531141.
It is a de Polignac number, because none of the positive numbers 2k-141135441413135 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 141135441413092 and 141135441413101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23148269 + ... + 28602678.
It is an arithmetic number, because the mean of its divisors is an integer number (11399672949966).
Almost surely, 2141135441413135 is an apocalyptic number.
141135441413135 is a deficient number, since it is larger than the sum of its proper divisors (41259325786321).
141135441413135 is a wasteful number, since it uses less digits than its factorization.
141135441413135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51792922.
The product of its digits is 172800, while the sum is 41.
Adding to 141135441413135 its reverse (531314144531141), we get a palindrome (672449585944276).
The spelling of 141135441413135 in words is "one hundred forty-one trillion, one hundred thirty-five billion, four hundred forty-one million, four hundred thirteen thousand, one hundred thirty-five".
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